0,32x=16x^2

Solution for 0,32x=16x^2 equation:

0.32x=16x^2

We move all terms to the left:

0.32x-(16x^2)=0

determiningTheFunctionDomain
-16x^2+0.32x=0

a = -16; b = 0.32; c = 0;
Δ = b2-4ac
Δ = 0.322-4·(-16)·0
Δ = 0.1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.32)-\sqrt{0.1024}}{2*-16}=\frac{-0.32-\sqrt{0.1024}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.32)+\sqrt{0.1024}}{2*-16}=\frac{-0.32+\sqrt{0.1024}}{-32}
$